Add two numbers represented as LinkedList
July 07, 2019 by Sandeep Bhardwaj | Tags: Leetcode Datastructure & Algorithms
Add two numbers represented as LinkedList
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Example:
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.
/**
* 2. Add Two Numbers
*
* You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse
* order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
* <p>
* You may assume the two numbers do not contain any leading zero, except the number 0 itself.
* <p>
* Example:
* <p>
* Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
* Output: 7 -> 0 -> 8
* Explanation: 342 + 465 = 807.
*/
public class AddTwoNumbers {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode output = null;
int carry = 0;
ListNode current = null;
while (l1 != null && l2 != null) {
int val = (l1.val + l2.val + carry) % 10;
carry = (l1.val + l2.val + carry) / 10;
l1 = l1.next;
l2 = l2.next;
if (output == null) {
output = new ListNode(val);
current = output;
} else {
current.next = new ListNode(val);
current = current.next;
}
}
while (l1 != null) {
int val = (l1.val + carry) % 10;
carry = (l1.val + carry) / 10;
l1 = l1.next;
current.next = new ListNode(val);
current = current.next;
}
while (l2 != null) {
int val = (l2.val + carry) % 10;
carry = (l2.val + carry) / 10;
l2 = l2.next;
current.next = new ListNode(val);
current = current.next;
}
if (carry != 0) {
current.next = new ListNode(carry);
}
return output;
}
}