Valid Parentheses
July 26, 2019 by Sandeep Bhardwaj | Tags: Leetcode Datastructure & Algorithms
Valid Parentheses
/**
* 20. Valid Parentheses
* <p>
* Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
* <p>
* An input string is valid if:
* <p>
* Open brackets must be closed by the same type of brackets.
* Open brackets must be closed in the correct order.
* Note that an empty string is also considered valid.
* <p>
* Example 1:
* <p>
* Input: "()"
* Output: true
* Example 2:
* <p>
* Input: "()[]{}"
* Output: true
* Example 3:
* <p>
* Input: "(]"
* Output: false
*/
public class ValidParentheses {
public boolean isValid(String s) {
Stack<Character> stack = new Stack<>();
for (int i = 0; i < s.length(); i++) {
char ch = s.charAt(i);
// for open parentheses push to stack
if (ch == '(' || ch == '{' || ch == '[') {
stack.push(ch);
continue;
}
if (stack.isEmpty()) {
return false;
}
char top = stack.pop();
if (ch == ')' && top != '(') {
return false;
}
if (ch == '}' && top != '{') {
return false;
}
if (ch == ']' && top != '[') {
return false;
}
}
return stack.isEmpty();
}
public boolean isValid2(String s) {
Stack<Character> stack = new Stack<Character>();
for (char c : s.toCharArray()) {
if (c == '(') {
stack.push(')');
} else if (c == '{') {
stack.push('}');
} else if (c == '[') {
stack.push(']');
} else if (stack.isEmpty() || stack.pop() != c) {
return false;
}
}
return stack.isEmpty();
}
}